Question

How can I solve a system of equations with fractions involving two unknowns?

Answer 1

substitution: substitute for I in eq. 2, since you know that I=e/(r+R). Then you can solve for r. when you get that, go back to eq. 1 and plug in the numbers

Answer 2

Multiply the equation with fractions by the denominator of the fraction; that will get rid of the fraction:. . I=e/(r + R). . I*(r + R) = e. . I*r + I*R = e. . Now you should be able to solve the equations by the usual methods.

Answer 3

well, start by substituting the provided values to get the real two equations. . L= 1.54 / (r+1). 1.4=1.54-Lr. . now you have two equations with two unknowns. there are several techniques to solve simultaneous equations. . I suggest substitution, substitue the expression for L in the first equation in for L in the second equation. . 1.4 = 1.54 - (1.54/(r+1)). . now you have one equation with one unknown. you should be able to do the algebra, it might start like this:. . subtract 1.54 from both sides ---> -.04 = -1.54/(r+1). . multiply (r+1) by both sides ---> -.04 r -.04 = -1.54. . add .04 ---------------------------> -.04 r = -1.5. . divide by -.04 -----------------------> r = 37.5. . go back and substitue r somewhere to get the value of L. . good luck,. keep at it

Answer 4

I = e/r+R = I = 1.54/r+1 (substituting given values) . . Vt = e - Ir =1.4 = 1.54 -r (substituting given values). . Then sub 1.54/r+1 for I. . Then 1.4 =1.54- r(1.54/r=1) then rearranging,. . 1.4 - 1.54 = -r(1.54/r+1) transpose, 1.4 - 1.54 = -r(1.54/r+1). . so -0.14 = -1.54r/(r+1) cross multiply , and. . -1.4r -.14 = -1.54r and, 1.4r = 0.14 , r = 0.1. . ergo , I = 1.54/1.1 = 1.4 Cheers

Answer 5

Substitute values in the equation. Start with eq #2. . 1.4=1.54 - (Ix1). . since anything times 1 is the same value. . 1.4 = 1.54- I. Moving the value from one side of the eq to other. . 1.4-1.54 = -I. . -0.04 =-I. . therefore I = 0.04. . Now substitute this and other values in eq 1. . 0.04 = 1.54/ (r+1). . 0.04 x (r+1) = 1.54. r+1 = 1.54/0.04. r+1 = 38.5. r=38.5-1. r = 37.5. . Two unknowns: I = 0.04 and r = 37.5. . Hope this helps!